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  3. Acyl substitution and derivative choice
  4. tert-Butyl phenylacetate by Steglich esterification

Organic Chemistry 2 · Acyl substitution and derivative choice

tert-Butyl phenylacetate by Steglich esterification

Draw the mechanism · Challenge

Conditions: DCC, DMAP (cat.), CH2Cl2

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The mechanism, step by step

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  1. Phenylacetic acid protonates DCC

    DCC turns the poor OH leaving group of a carboxylic acid into a good one. The acid first gives its proton to a nitrogen of the carbodiimide, making the central carbon electrophilic.

    The curved arrows

    • A DCC nitrogen lone pair bonds to the carboxylic acid proton.
    • The O–H bond pair stays on oxygen as the carboxylate forms.
  2. The carboxylate adds to form the O-acylisourea

    The phenylacetate oxygen attacks the central carbon of protonated DCC, and the C=N⁺ π pair moves onto nitrogen. The O-acylisourea is an activated acyl donor.

    The curved arrows

    • A carboxylate oxygen lone pair forms the O–C bond to the carbodiimide carbon.
    • The C=N⁺ π electrons move onto the protonated nitrogen.
  3. DMAP intercepts the O-acylisourea

    tert-Butanol is too hindered to attack the O-acylisourea quickly; left alone, it would undergo O→N acyl migration to an unreactive N-acylurea. Catalytic DMAP, a small strong nucleophile, attacks the acyl carbon first.

    The curved arrows

    • The DMAP ring nitrogen lone pair forms a new N–C bond to the acyl carbon.
    • The C=O π electrons move onto oxygen.
  4. The isourea anion leaves

    The alkoxide re-forms C=O and the isourea oxygen leaves as an anion. The N-acylpyridinium ion is a very reactive acyl donor that cannot rearrange.

    The curved arrows

    • The oxygen lone pair rebuilds the carbonyl π bond.
    • The C–O bond to the isourea breaks onto its oxygen.
  5. tert-Butanol attacks the acylpyridinium ion

    Even the hindered tertiary alcohol adds to the activated acylpyridinium carbonyl. The tetrahedral intermediate carries a positively charged oxonium oxygen.

    The curved arrows

    • The tert-butanol oxygen lone pair forms the new O–C bond.
    • The C=O π pair moves onto oxygen.
  6. DMAP is released

    The alkoxide re-forms C=O and neutral DMAP leaves, so the catalyst is regenerated. The protonated ester remains.

    The curved arrows

    • The oxygen lone pair rebuilds the carbonyl π bond.
    • The C–N bond pair returns to the DMAP ring nitrogen.
  7. The isourea anion becomes DCU

    The isourea anion takes the oxonium proton on nitrogen: its O⁻ forms C=O while the C=N π pair bonds the proton. This gives dicyclohexylurea (DCU), whose strong C=O pays for the whole coupling.

    The curved arrows

    • The oxygen lone pair forms the C=O π bond of the urea.
    • The C=N π electrons bond that nitrogen to the oxonium proton.
    • The O–H pair returns to the ester oxygen.
  8. tert-Butyl phenylacetate

    tert-Butyl phenylacetate forms, DMAP is regenerated, and DCU precipitates from dichloromethane. The Steglich method makes tert-butyl esters under neutral conditions where Fischer esterification fails.

What you'll practice

Draw the Steglich esterification of phenylacetic acid with tert-butanol, showing DMAP intercepting the O-acylisourea and DCU forming at the end.

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Tags

  • #SteglichEsterification
  • #Esterification
  • #Catalysis
  • #MechanismDrawing

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