Organic Chemistry 1 · Alkene addition and regiochemistry
9-BBN hydroboration of 3,3-dimethylbut-1-ene
Conditions: 9-BBN, THF; then H2O2, NaOH, H2O
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The mechanism, step by step
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Concerted syn hydroboration
In one concerted four-centre step the π electrons of 3,3-dimethylbut-1-ene bond C1, the terminal CH2 to the empty p orbital of boron in 9-BBN, while the B–H hydrogen moves to C2, next to the tert-butyl group. Boron and hydrogen add to the same face (syn), and no carbocation forms. Because no carbocation forms, the tert-butyl group has no chance to undergo a methyl shift.
The curved arrows
- The C=C π pair forms the C–B bond at C1, the terminal CH2, the less hindered alkene carbon.
- The B–H bond pair delivers hydrogen to C2, next to the tert-butyl group on the same face.
Hydroperoxide adds to boron
In the oxidation stage, hydroperoxide ion (HOO⁻, formed from H2O2 and NaOH) bonds to the empty p orbital of boron in the trialkylborane, giving a negatively charged borate.
The curved arrows
- A lone pair on the negatively charged peroxide oxygen bonds to boron.
Alkyl shift from boron to oxygen
The alkyl group bonded to boron migrates to the adjacent oxygen with its bonding pair as the weak O–O bond breaks and hydroxide leaves. The migrating carbon keeps its configuration, so oxygen replaces boron at exactly the carbon boron occupied.
The curved arrows
- The C–B bond pair moves the carbon onto the neighbouring oxygen, forming the C–O bond.
- The O–O bond pair leaves with the far oxygen as hydroxide.
Hydroxide adds to boron
Boron is electron-deficient again in the borate ester, so a hydroxide ion bonds to it. This sets up cleavage of the B–O bond to the new alkoxy oxygen.
The curved arrows
- A hydroxide lone pair bonds to boron.
Release the alkoxide
The B–O bond to the alkoxy oxygen breaks with both electrons going to oxygen, releasing the alkoxide and a hydroxyborane by-product.
The curved arrows
- The B–O bond pair stays on the alkoxy oxygen, giving the alkoxide.
Protonate the alkoxide
Water in the basic oxidation mixture gives a proton to the alkoxide, forming 3,3-dimethylbutan-1-ol and regenerating hydroxide.
The curved arrows
- The alkoxide lone pair takes a proton from water.
- The water O–H bond pair stays on oxygen as hydroxide.
3,3-dimethylbutan-1-ol
3,3-dimethylbutan-1-ol carries the OH on C1, the terminal CH2, the carbon that boron bonded to: the anti-Markovnikov orientation. The tert-butyl skeleton is intact: no methyl shift happened at any point.
What you'll practice
Draw hydroboration of 3,3-dimethylbut-1-ene by 9-BBN, then the peroxide oxidation to 3,3-dimethylbutan-1-ol with the carbon skeleton unchanged.
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