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  1. Practice problems
  2. Orgo 2
  3. Amine basicity and electronic structure
  4. Compute amine speciation

Organic Chemistry 2 · Amine basicity and electronic structure

Compute amine speciation

Calculate · Application

Conditions: Given teaching value pKa(BH⁺) = 9.0 in water; buffer fixes pH = 8.0. Ignore activity corrections.

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The question

What fraction of total B + BH⁺ is BH⁺?

Reveal the answer and explanation

Answer and explanation

  1. Correct answer 10/11, approximately 91%.

    [B]/[BH⁺] = 10⁻¹; one part B and ten parts BH⁺ total eleven.

  2. Not this one 1/10, or 10%.

    This confuses the unprotonated-to-protonated ratio with the protonated fraction.

  3. Not this one 1/2, or 50%.

    Equal populations require pH = pKa, not a one-unit difference.

Worked solution

Henderson–Hasselbalch gives [B]/[BH⁺] = 10^(8−9) = 0.1. Set BH⁺ = 10 and B = 1; the protonated fraction is 10/(10+1) = 10/11.

What you'll practice

Convert a pH–pKa difference into a protonated fraction.

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Tags

  • #Buffers
  • #Amines
  • #pKa
  • #Calculations

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