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  3. Claisen condensation and conjugate addition
  4. Aza-Baylis–Hillman of an N-tosyl imine with MVK

Organic Chemistry 2 · Claisen condensation and conjugate addition

Aza-Baylis–Hillman of an N-tosyl imine with MVK

Draw the mechanism · Challenge

Conditions: DABCO (cat.), THF

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← All Claisen condensation and conjugate addition problemsNext problem: Methyl 3-(piperidin-1-yl)propanoate by aza-Michael addition →

The mechanism, step by step

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  1. DABCO adds to methyl vinyl ketone

    The DABCO nitrogen adds to the terminal CH2 of methyl vinyl ketone. The resulting zwitterion holds an ammonium ion next to a ketone enolate, drawn here with the charge on the α-carbon that reacts next.

    The curved arrows

    • The DABCO nitrogen lone pair bonds to the β-carbon of the enone.
    • The C=C π pair moves onto the α-carbon, stabilized by the ketone.
  2. Mannich-type addition to the imine

    The enolate α-carbon attacks the imine carbon of the N-tosyl imine. The electron-withdrawing tosyl group makes the C=N carbon electrophilic and stabilizes the sulfonamide anion that forms.

    The curved arrows

    • The enolate carbon forms the C–C bond to the imine carbon.
    • The C=N π pair moves onto nitrogen, giving a sulfonamide anion.
  3. Protonate the sulfonamide nitrogen

    Trace water (assumed proton shuttle) protonates the sulfonamide anion, giving the N–H sulfonamide and hydroxide. Moving the α-hydrogen straight to nitrogen inside the molecule is not drawn.

    The curved arrows

    • The nitrogen lone pair takes a proton from water.
    • The O–H pair stays on oxygen as hydroxide.
  4. Remove the α-hydrogen

    Hydroxide removes the hydrogen on the carbon between the ketone and the ammonium-bearing CH2, regenerating a ketone enolate. This sets up elimination of the amine.

    The curved arrows

    • The hydroxide lone pair takes the acidic α-hydrogen.
    • The C–H pair stays on carbon, stabilized by the ketone.
  5. E1cB release of DABCO

    The carbanion re-forms the C=C bond and expels neutral DABCO. The catalyst is regenerated and the α-methylene ketone is formed.

    The curved arrows

    • The carbanion lone pair forms the C=C π bond.
    • The C–N bond breaks and DABCO leaves with its lone pair.
  6. N-(2-Methylene-3-oxo-1-phenylbutyl)-4-methylbenzenesulfonamide

    The product is N-(2-methylene-3-oxo-1-phenylbutyl)-4-methylbenzenesulfonamide, racemic at the new benzylic stereocentre. The imine carbon has been joined to the α-carbon of methyl vinyl ketone with the C=C bond kept.

What you'll practice

Draw the DABCO-catalysed aza-Baylis–Hillman reaction of an N-tosyl benzaldimine with methyl vinyl ketone: zwitterionic enolate formation, Mannich-type addition to the imine, proton relay and E1cB release of DABCO.

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Tags

  • #BaylisHillman
  • #Sulfonamides
  • #ConjugateAddition

More Claisen condensation and conjugate addition problems

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  • Benzoin by cyanide-catalysed benzoin condensation
  • Diethyl phenylmalonate from ethyl phenylacetate
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