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  2. Orgo 2
  3. Claisen condensation and conjugate addition
  4. Claisen of ethyl isobutyrate with trityl sodium

Organic Chemistry 2 · Claisen condensation and conjugate addition

Claisen of ethyl isobutyrate with trityl sodium

Draw the mechanism · Challenge

Conditions: Ph₃C⁻ Na⁺ (1 equiv), Et₂O; then H3O⁺

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← All Claisen condensation and conjugate addition problemsNext problem: Self-Claisen of ethyl phenylacetate to a β-keto ester →

The mechanism, step by step

Next plays each step's curved arrows and explains them. The written steps are below.

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  1. Deprotonate irreversibly with the trityl anion

    The trityl anion (pKa of triphenylmethane ≈ 31) removes the single α-hydrogen of ethyl isobutyrate (pKa ≈ 25). Because the base is about six pKa units stronger than the enolate, this deprotonation runs to completion and does not reverse.

    The curved arrows

    • The lone pair on the trityl carbon bonds to the tertiary α-hydrogen.
    • The C–H pair stays on the α-carbon, giving the fully formed ester enolate.
  2. Enolate adds to a second ester

    The tertiary enolate carbon attacks the carbonyl carbon of a second ethyl isobutyrate molecule. Both partners are crowded, so this addition is slow, but nothing competes with it once all the ester enolate has formed.

    The curved arrows

    • The enolate carbon lone pair forms the new C–C bond to the second ester carbonyl carbon.
    • The C=O π pair moves onto oxygen, giving a tetrahedral alkoxide.
  3. Collapse and expel ethoxide

    The alkoxide re-forms the C=O bond and pushes out ethoxide, giving the β-keto ester. Its carbon between the carbonyls carries two methyls and no hydrogen, so no stabilized anion can form; the full conversion was secured by the first, irreversible deprotonation instead.

    The curved arrows

    • An oxygen lone pair re-forms the C=O π bond.
    • The C–O bond to the ethoxy group breaks and ethoxide leaves with the pair.
  4. Acidic workup

    Hydronium, added after the reaction, protonates the ethoxide released in the condensation. The neutral β-keto ester is isolated before any base can cleave it.

    The curved arrows

    • The ethoxide oxygen lone pair bonds to a proton of hydronium.
    • The O–H pair returns to oxygen, releasing water.
  5. Ethyl 2,2,4-trimethyl-3-oxopentanoate

    The product is ethyl 2,2,4-trimethyl-3-oxopentanoate, with triphenylmethane, ethanol and water as by-products. Sodium ethoxide fails here because the product cannot be trapped as an anion, so retro-Claisen cleavage would undo it.

What you'll practice

Draw the Claisen condensation of ethyl isobutyrate driven by trityl sodium: irreversible enolate formation, addition to a second ester, loss of ethoxide and the workup to ethyl 2,2,4-trimethyl-3-oxopentanoate.

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Tags

  • #ClaisenCondensation
  • #Equilibrium
  • #pKa

More Claisen condensation and conjugate addition problems

  • Self-Claisen of ethyl phenylacetate to a β-keto ester
  • Ethyl benzoylacetate by crossed Claisen of ethyl acetate and ethyl benzoate
  • Crossed Claisen of cyclohexanone and diethyl oxalate
  • Formylation of cyclohexanone with ethyl formate
  • Crossed Claisen of ethyl propanoate and diethyl oxalate
  • Ethyl 2-methyl-3-oxopropanoate by formylation of ethyl propanoate
  • 3-Oxocyclohexane-1-carbonitrile by conjugate addition of cyanide to cyclohexenone
  • Decarboxylation of benzylmalonic acid on heating

Keep practicing

  • Claisen condensation and conjugate addition: practice problems
  • Free lesson: Claisen condensation and conjugate addition
  • All practice problems

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