Why heat favours elimination

Resposta e explicação

1. Resposta correta Elimination produces more molecules than substitution, so it has the larger positive ΔS, and the −TΔS term favours it more at higher temperature.

   Both pathways release H⁺ and Br⁻, but substitution also binds an ethanol molecule into the product while elimination does not, so elimination ends with more free particles. That extra entropy matters more as T rises.

2. Esta não Heat turns ethanol into a strong base.

   Ethanol stays a weak base at any practical temperature; the mechanism is still E1 through the cation.

3. Esta não The carbocation is less stable at high temperature, so it rearranges to an alkene.

   An alkene is not a rearranged cation; the cation loses a β-hydrogen. The effect is about entropy, not cation stability.

4. Esta não Substitution products decompose on heating, leaving only alkenes.

   Some ether still forms at reflux; the product ratio shifts because the two competing pathways respond differently to temperature, not because the ether is destroyed.